(Q11). Length of the shadow of a 15 meter high pole is 5√3 meters at 7 o'clock in the morning. Then, what is the angle of elevation of the Sun rays with the ground at the time ?

Solution :

Height of the pole = 15 m

Length of the shadow = 5√3 m

Let the angle of elevation be 'θ'.

Then from the figure

tanθ =

√

=

5 × √ × √

× √

= √

tanθ = √ = tan °

∴θ = °

∴ Angle of elevation of Sun rays with the ground = °.